#Median date calculator mod
#Median date calculator code

I know that I am happy myself if I find 'readymade' functions that are easy to include in my projects, so I decided to quickly share: function mysql_percentile($table, $column, $where, $percentile = 0. 15.10 - MEDIAN - Teradata Database Teradata Database SQL Functions, Operators, Expressions, and Predicates Product Teradata Database. median(table_name, column_name, where_condition) Īs i just needed a median AND percentile solution, I made a simple and quite flexible function based on the findings in this thread.

WHERE ', where_clause, ' ORDER BY x.', column_name, ' SELECT t1.', column_name, ' AS 'middle_values' FROM 'SELECT AVG(middle_values) AS 'median' FROM ( IF where_clause IS NULL OR where_clause = '' THEN Optionally, you could also do this in a stored procedure: DROP PROCEDURE IF EXISTS median ĬREATE PROCEDURE median (table_name VARCHAR(255), column_name VARCHAR(255), where_clause VARCHAR(255)) from there we can select the n-th element on the position: count div 2 + 1 The Statement creates a helper table like

#Median date calculator mod

Create an index n for every := + 1) mod o.c AS mod o.c=0, o.c, AS n, INSERT INTO table_median (id, val) VALUES

If you have a WHERE condition, replace 'WHERE 1' (2 occurrences) with your where conditionĪ comment on this page in the MySQL documentation has the following suggestion: - (mostly) High Performance scaling MEDIAN function per groupĬREATE TABLE table_median (id INTEGER(11),val INTEGER(11)).

Replace 'median_column' (3 occurrences) with the column name you'd like to find a median for.

#Median date calculator code

Replace 'median_table' (2 occurrences) in the above code with the name of your table.

the following condition will return 1 record for odd number sets, or 2 records for even number sets. SELECT t1.median_column AS 'middle_values' FROM So, here's velcro's solution patched to handle both odd and even number sets: SELECT AVG(middle_values) AS 'median' FROM ( Since there are 10 people in the set, to get the median, we have to add the 5 th and 6 th values (Kat and Luigi’s annual income) and divide it by 2. Medians are defined as either 1) the middle number on odd numbered sets, or 2) the average of the two middle numbers on even number sets. The total income of the people in the restaurant is 506,000, with a mean income of 50,600. Velcro's answer from above is close, but it does not calculate correctly for result sets with an even number of rows. Unfortunately, neither TheJacobTaylor's nor velcrow's answers return accurate results for current versions of MySQL.